3t+3=16+t^2

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Solution for 3t+3=16+t^2 equation: 



3t+3=16+t^2

We move all terms to the left:

3t+3-(16+t^2)=0

We get rid of parentheses

-t^2+3t-16+3=0

We add all the numbers together, and all the variables

-1t^2+3t-13=0

a = -1; b = 3; c = -13;
Δ = b2-4ac
Δ = 32-4·(-1)·(-13)
Δ = -43
Delta is less than zero, so there is no solution for the equation

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